4(sin^2x)-13(cosx)+9=0

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Solution for 4(sin^2x)-13(cosx)+9=0 equation: 


Simplifying
4(sin2x) + -13(cosx) + 9 = 0

Reorder the terms:
9 + -13cosx + 4in2sx = 0

Solving
9 + -13cosx + 4in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -13cosx + -9 + 4in2sx = 0 + -9

Reorder the terms:
9 + -9 + -13cosx + 4in2sx = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -13cosx + 4in2sx = 0 + -9
-13cosx + 4in2sx = 0 + -9

Combine like terms: 0 + -9 = -9
-13cosx + 4in2sx = -9

Add '-4in2sx' to each side of the equation.
-13cosx + 4in2sx + -4in2sx = -9 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
-13cosx + 0 = -9 + -4in2sx
-13cosx = -9 + -4in2sx

Divide each side by '-13osx'.
c = 0.6923076923o-1s-1x-1 + 0.3076923077in2o-1

Simplifying
c = 0.6923076923o-1s-1x-1 + 0.3076923077in2o-1

Reorder the terms:
c = 0.3076923077in2o-1 + 0.6923076923o-1s-1x-1

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